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Let omega be a complex cube root of unit...

Let `omega` be a complex cube root of unity with `omega ne 1`. A fair die is thrown three times. If `r_(1), r_(2)` and `r_(3)` are the numbers obtained on the die, then the probability that `omega^(r_(1)) + omega^(r_(2)) + omega^(r_(3)) = 0` is

A

`(1)/(18)`

B

`(1)/(9)`

C

`(2)/(9)`

D

`(1)/(36)`

Text Solution

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The correct Answer is:
C
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