The equation `2 "cos"^(2)((x)/(2))"sin"^(2) x = x^(2) + (1)/(x^(2)), 0 le x le (pi)/(2)` has

The number of solutions of 2"cos"^(2)((x)/(2))"sin"^(2) x =x^(2) + (1)/(x^(2)), 0 le x le (pi)/(2), is

If 0 le x le pi/2 then

The equation 2cos^(2)(x/2) sin^2x=x^(2)+x^(-2), 0 lt x^(-2), 0 lt x le pi/2 has

The equation 2sin^(2)((x)/(2))cos^(2)x=x+(1)/(x),0 lt x le(pi)/(2) has

The number of solution(s) of 2cos^(2)(x/2)sin^(2)x=x^(2)+1/x^(2), 0 le x le pi//2 , is/ are-

The solution of the equation "cos"^(2) x-2 "cos" x = 4 "sin" x - "sin" 2x (0 le x le pi) , is

Find the solution of the equation ( sin x + cos x ) sin 2 x =a(sin^(3) x + cos^(3) x) located between (pi)/(2) and pi and for which values of 'a' does this equation have at most one solution satisfying the condition (pi)/(2) le x le pi .

Solve : cos 3x + cos 2x = sin ""(3)/(2) x + sin "" (1)/(2) x, 0 lt x le pi.

Prove that sin^(-1) cos (sin^(-1) x) + cos^(-1) x) = (pi)/(2), |x| le 1

Find the number of solutions of the equation 2 sin^(2) x + sin^(2) 2x = 2 , sin 2x + cos 2x = tan x in [0, 4 pi] satisfying the condition 2 cos^(2) x + sin x le 2 .