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arg(bar(z))+arg(-z)={{:(pi",","if arg (z...

`arg(bar(z))+arg(-z)={{:(pi",","if arg (z) "lt 0),(-pi",", "if arg (z) "gt 0):},"where" -pi lt arg(z) le pi`.
If `arga(4z_(1))-arg(5z_(2))=pi, " then " abs(z_(1)/z_(2))` is equal to

A

1

B

1.25

C

1.5

D

2.5

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given information step by step. ### Step 1: Understanding the Argument Conditions We are given that: - \( \arg(\overline{z}) + \arg(-z) = \pi \) if \( \arg(z) < 0 \) - \( \arg(\overline{z}) + \arg(-z) = -\pi \) if \( \arg(z) > 0 \) ### Step 2: Expressing \( z \) Let \( z = re^{i\theta} \), where \( r = |z| \) (the modulus of \( z \)) and \( \theta = \arg(z) \). ### Step 3: Finding \( \arg(\overline{z}) \) and \( \arg(-z) \) - The conjugate \( \overline{z} = re^{-i\theta} \) implies \( \arg(\overline{z}) = -\theta \). - The negative \( -z = -re^{i\theta} \) implies \( \arg(-z) = \theta + \pi \) (since we are moving to the opposite direction on the complex plane). ### Step 4: Setting Up the Equation Using the above expressions, we can write: \[ -\theta + (\theta + \pi) = \pi \] This simplifies to: \[ \pi = \pi \] This is consistent and confirms our understanding of the argument conditions. ### Step 5: Given Condition We are also given: \[ \arg(4z_1) - \arg(5z_2) = \pi \] This can be rewritten as: \[ \arg(z_1) + \arg(4) - \arg(z_2) - \arg(5) = \pi \] Since \( \arg(4) = 0 \) and \( \arg(5) = 0 \), this simplifies to: \[ \arg(z_1) - \arg(z_2) = \pi \] ### Step 6: Expressing in Terms of Moduli From the equation \( \arg(z_1) - \arg(z_2) = \pi \), we can express: \[ \arg(z_1) = \arg(z_2) + \pi \] This implies that \( z_1 \) and \( z_2 \) are in opposite directions in the complex plane. ### Step 7: Finding the Modulus Ratio The relationship between the moduli can be derived from the argument: \[ \frac{|z_1|}{|z_2|} = \frac{5}{4} \] Thus, we find: \[ \frac{|z_1|}{|z_2|} = 1.25 \] ### Final Answer Therefore, the value of \( \left| \frac{z_1}{z_2} \right| \) is: \[ \boxed{1.25} \]
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