Home
Class 12
MATHS
Find the equation of the plane contai...

Find the equation of the plane containing the lines `(x-5)/4=(y-7)/4=(z+3)/(-5)a n d(x-8)/7=(y-4)/1=(z-5)/3dot`

Text Solution

Verified by Experts

The correct Answer is:
`17x-47y-24z+172=0`
Promotional Banner

Topper's Solved these Questions

  • THREE DIMENSIONAL COORDINATE SYSTEM

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 4|7 Videos

  • THREE DIMENSIONAL COORDINATE SYSTEM

    ARIHANT MATHS ENGLISH|Exercise Exercise (Single Option Correct Type Questions)|96 Videos

  • THREE DIMENSIONAL COORDINATE SYSTEM

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 2|10 Videos

  • THEORY OF EQUATIONS

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|35 Videos

  • TRIGONOMETRIC EQUATIONS AND INEQUATIONS

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|12 Videos

Similar Questions

Explore conceptually related problems

Show that the lines (x-5)/4=(y-7)/4=(z+3)/(-5) and (x-8)/7=(y-4)/1=(z-5)/3 intersect each other

Find the equation of the plane containing the line (x+1)/3=(y-3)/5=(z+2)/(-2) and the point (0,7,-7) and show that the line x/1=(y-7)/(-3)=(z+7)/2 also lies in the same plane.

The equation of the plane which is equally inclined to the lines (x-1)/2=y/(-2)=(z+2)/(-1)a n d=(x+3)/8=(y-4)/1=z/(-4) and passing through the origin is/are a. 14 x-5y-7z=0 b. 2x+7y-z=0 c. 3x-4y-z=0 d. x+2y-5z=0

The equation of the plane which is equally inclined to the lines (x-1)/2=y/(-2)=(z+2)/(-1)a n d=(x+3)/8=(y-4)/1=z/(-4) and passing through the origin is/are a. 14 x-5y-7z=0 b. 2x+7y-z=0 c. 3x-4y-z=0 d. x+2y-5z=0

Find the equation of the plane passing through the line (x-1)/5=(y+2)/6=(z-3)/4 and point (4,3,7)dot

The perpendicular distance from the origin to the plane containing the two lines, (x+2)/3=(y-2)/5=(z+5)/7 and (x-1)/1=(y-4)/4=(z+4)/7 is: (a) 11sqrt6 (b) 11/(sqrt6) (c) 11 (d) 6sqrt(11)

If the distance between the plane ax 2y + z = d and the plane containing the lines (x-1)/2=(y-2)/3=(z-3)/4 and (x-2)/3=(y-3)/4=(z-4)/5 is sqrt6 , then value of |d| is

Find the shortest distance between the lines (x-1)/2=(y-2)/3=(z-3)/4a n d(x-2)/3=(y-4)/4=(z-5)/5 .

Find the shortest distance between the lines (x-1)/2=(y-2)/3=(z-3)/4a n d(x-2)/3=(y-4)/4=(z-5)/5 .

Find the shortest distance between the lines (x-1)/2=(y-2)/3=(z-3)/4a n d(x-2)/3=(y-4)/4=(z-5)/5 .