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If the distance between the points (a, 2...

If the distance between the points (a, 2) and (3, 4) be 8, then a equals to

A

`2+3sqrt(3)`

B

`2-3 sqrt(15)`

C

`2pm3sqrt(15)`

D

`3pm2sqrt(15)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the distance formula and the information provided in the question. ### Step 1: Understand the distance formula The distance \( d \) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by the formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] ### Step 2: Identify the points In this case, the points are \((a, 2)\) and \((3, 4)\). Here, \(x_1 = a\), \(y_1 = 2\), \(x_2 = 3\), and \(y_2 = 4\). ### Step 3: Set up the equation We are given that the distance between these two points is 8. Therefore, we can set up the equation: \[ \sqrt{(3 - a)^2 + (4 - 2)^2} = 8 \] ### Step 4: Simplify the equation First, simplify \( (4 - 2)^2 \): \[ (4 - 2)^2 = 2^2 = 4 \] Now, substitute this back into the equation: \[ \sqrt{(3 - a)^2 + 4} = 8 \] ### Step 5: Square both sides To eliminate the square root, square both sides of the equation: \[ (3 - a)^2 + 4 = 8^2 \] This simplifies to: \[ (3 - a)^2 + 4 = 64 \] ### Step 6: Isolate the squared term Subtract 4 from both sides: \[ (3 - a)^2 = 64 - 4 \] \[ (3 - a)^2 = 60 \] ### Step 7: Take the square root Now, take the square root of both sides: \[ 3 - a = \pm \sqrt{60} \] ### Step 8: Solve for \( a \) This gives us two equations: 1. \( 3 - a = \sqrt{60} \) 2. \( 3 - a = -\sqrt{60} \) For the first equation: \[ a = 3 - \sqrt{60} \] For the second equation: \[ a = 3 + \sqrt{60} \] ### Step 9: Simplify \( \sqrt{60} \) We can simplify \( \sqrt{60} \): \[ \sqrt{60} = \sqrt{4 \cdot 15} = 2\sqrt{15} \] Thus, we have: 1. \( a = 3 - 2\sqrt{15} \) 2. \( a = 3 + 2\sqrt{15} \) ### Final Answer The values of \( a \) are: \[ a = 3 - 2\sqrt{15} \quad \text{or} \quad a = 3 + 2\sqrt{15} \]
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ARIHANT MATHS ENGLISH-COORDINATE SYSTEM AND COORDINATES -Exercise For Session 2
  1. If the distance between the points (a, 2) and (3, 4) be 8, then a equa...

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  2. The three points (-2, 2), (8, -2) and (-4, -3) are the vertices of

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  3. The distance between the points (3,pi/4) and (7,(5pi)/4)

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  4. Let A(6, -1), B (1, 3) and C (x, 8) be three points such that AB = BC ...

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  5. The points (a+1,1), (2a+1,3) and (2a+2,2a) are collinear if

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  6. Let A=(3,4) and B is a variable point on the lines |x| =6. IF A Blt...

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  7. The number of points on X-axis which are at a distance c units (c lt 3...

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  8. The point on the axis of y which its equidistant from (-1, 2) and (3, ...

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  9. Find the distance between the points (at(1)^(2), 2 at(1)) and (at(2)^(...

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  10. If P and Q are two points whose coordinates are (a t^2,2a t)a n d(a/(t...

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  11. Show that the points (3, 4), (8, -6) and (13, 9) are the vertices of a...

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  12. Show that four points (0,-1),(6,7),(-2,3)a n d(8,3) are the vertices o...

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  13. Find the circumcentre and circumradius of the triangle whose vertices ...

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  14. The vertices of a triangle are A(1,1),\ B(4,5)a n d\ C(6, 13)dot Find ...

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  15. The opposite vertices of a square are (2, 6) and (0, -2). Find the coo...

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  16. If the point (x , y) is equidistant from the points (ab , b-a) and (a-...

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  17. if a and bbetween 0 and 1 such that the points (a, 1). (1, b) and (0, ...

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  18. An equilateral triangle has two vertices at the points (3, 4) and (-2,...

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  19. If P be any point in the plane of square ABCD, prove that PA^(2)+PC^...

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