Home
Class 12
MATHS
If the lines represented by x^(2)-2pxy-y...

If the lines represented by `x^(2)-2pxy-y^(2)=0` are rotated about the origin through an angle `theta`, one clockwise direction and other in anti-clockwise direction, then the equation of the bisectors of the angle between the lines in the new position is

Text Solution

AI Generated Solution

The correct Answer is:
To find the equation of the bisectors of the angle between the lines represented by the equation \(x^2 - 2pxy - y^2 = 0\) after rotating them about the origin through an angle \(\theta\), we will follow these steps: ### Step-by-Step Solution: 1. **Identify the coefficients**: The given equation is \(x^2 - 2pxy - y^2 = 0\). We can identify the coefficients \(a\), \(b\), and \(h\) from the general form \(ax^2 + 2hxy + by^2 = 0\): - \(a = 1\) - \(b = -1\) - \(h = -p\) 2. **Use the formula for the bisectors**: The equation of the bisectors of the angle between the lines is given by: \[ \frac{x^2 - y^2}{a - b} = \frac{xy}{h} \] Substituting the values of \(a\), \(b\), and \(h\): - \(a - b = 1 - (-1) = 2\) - \(h = -p\) Thus, the equation becomes: \[ \frac{x^2 - y^2}{2} = \frac{xy}{-p} \] 3. **Cross-multiply to eliminate the fraction**: We can cross-multiply to simplify the equation: \[ x^2 - y^2 = -\frac{2xy}{p} \] 4. **Rearranging the equation**: Rearranging gives: \[ -px^2 + py^2 + 2xy = 0 \] 5. **Multiply through by -1**: To make the equation neater, we can multiply the entire equation by -1: \[ px^2 - py^2 - 2xy = 0 \] This is the equation of the bisectors of the angle between the lines in their new position after rotation. ### Final Answer: The equation of the bisectors of the angle between the lines after rotation is: \[ px^2 - py^2 - 2xy = 0 \]
Promotional Banner

Topper's Solved these Questions

  • PAIR OF STRAIGHT LINES

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 1|9 Videos
  • PAIR OF STRAIGHT LINES

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 2|10 Videos
  • MONOTONICITY MAXIMA AND MINIMA

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|29 Videos
  • PARABOLA

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|36 Videos

Similar Questions

Explore conceptually related problems

The equations of bisectors of the angles between the lines |x|=|y| are

Find the equation of the bisectors of the angle between the lines represented by 3x^2-5xy+4y^2=0

The equation of the bisectors of angle between the lines x^(2)-4xy+y^(2)=0 is

If the represented by the equation 3y^2-x^2+2sqrt(3)x-3=0 are rotated about the point (sqrt(3),0) through an angle of 15^0 , one in clockwise direction and the other in anticlockwise direction, so that they become perpendicular, then the equation of the pair of lines in the new position is

If the represented by the equation 3y^2-x^2+2sqrt(3)x-3=0 are rotated about the point (sqrt(3),0) through an angle of 15^0 , on in clockwise direction and the other in anticlockwise direction, so that they become perpendicular, then the equation of the pair of lines in the new position is (1) y^2-x^2+2sqrt(3)x+3=0 (2) y^2-x^2+2sqrt(3)x-3=0 (3) y^2-x^2-2sqrt(3)x+3=0 (4) y^2-x^2+3=0

If the represented by the equation 3y^2-x^2+2sqrt(3)x-3=0 are rotated about the point (sqrt(3),0) through an angle of 15^0 , on in clockwise direction and the other in anticlockwise direction, so that they become perpendicular, then the equation of the pair of lines in the new position is y^2-x^2+2sqrt(3)x+3=0 y^2-x^2+2sqrt(3)x-3=0 y^2-x^2-2sqrt(3)x+3=0 y^2-x^2+3=0

Find the equation of the bisector of the acute angle between the lines 3x-4y+7=0 and 12x+5y-2=0 .

Find the equation of the bisector of the obtuse angle between the lines 3x-4y+7=0 and 12 x+5y-2=0.

The angle between the lines represented by x^(2)-y^(2)=0 is

The lines bisecting the angle between the bisectors of the angles between the lines ax^(2)+2hxy+by^(2)=0 are given by