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A point moves so that the distance betwe...

A point moves so that the distance between the foot of perpendiculars from it on the lines `a x^2+2hx y+b y^2=0` is a constant `2d` . Show that the equation to its locus is `(x^2+y^2)(h^2-a b)=d^2{(a-b)^2+4h^2}dot`

Text Solution

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The correct Answer is:
`(x^2+y^2)(h^2-ab)=k^2{(a-b)^2+4h^2}`.
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