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Find the equation to the parabola whose axis parallel to the y-axis and which passes through the points (0,4)(1,9) and (4,5) and determine its latusrectum.

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To find the equation of the parabola whose axis is parallel to the y-axis and which passes through the points (0, 4), (1, 9), and (4, 5), we can follow these steps: ### Step 1: Set up the equation of the parabola Since the axis of the parabola is parallel to the y-axis, we can express the equation of the parabola in the standard form: \[ y = ax^2 + bx + c \] ### Step 2: Substitute the points into the equation We will substitute each of the given points into the equation to create a system of equations. 1. For the point (0, 4): \[ 4 = a(0)^2 + b(0) + c \] This simplifies to: \[ c = 4 \] 2. For the point (1, 9): \[ 9 = a(1)^2 + b(1) + c \] Substituting \( c = 4 \): \[ 9 = a + b + 4 \] This simplifies to: \[ a + b = 5 \] (Equation 1) 3. For the point (4, 5): \[ 5 = a(4)^2 + b(4) + c \] Substituting \( c = 4 \): \[ 5 = 16a + 4b + 4 \] This simplifies to: \[ 16a + 4b = 1 \] Dividing through by 4 gives: \[ 4a + b = \frac{1}{4} \] (Equation 2) ### Step 3: Solve the system of equations Now we have a system of two equations: 1. \( a + b = 5 \) 2. \( 4a + b = \frac{1}{4} \) We can solve this system by elimination or substitution. Let's use elimination. Subtract Equation 1 from Equation 2: \[ (4a + b) - (a + b) = \frac{1}{4} - 5 \] This simplifies to: \[ 3a = \frac{1}{4} - \frac{20}{4} = -\frac{19}{4} \] Thus, \[ a = -\frac{19}{12} \] Now substitute \( a \) back into Equation 1 to find \( b \): \[ -\frac{19}{12} + b = 5 \] \[ b = 5 + \frac{19}{12} = \frac{60}{12} + \frac{19}{12} = \frac{79}{12} \] ### Step 4: Write the final equation of the parabola Now we have: - \( a = -\frac{19}{12} \) - \( b = \frac{79}{12} \) - \( c = 4 \) Substituting these values into the equation \( y = ax^2 + bx + c \): \[ y = -\frac{19}{12}x^2 + \frac{79}{12}x + 4 \] To express this in a standard form: \[ 12y = -19x^2 + 79x + 48 \] Rearranging gives: \[ 19x^2 - 79x + 12y = 48 \] ### Step 5: Determine the latus rectum The latus rectum \( L \) of a parabola is given by the formula: \[ L = \frac{1}{|a|} \] Here, \( a = -\frac{19}{12} \), so: \[ L = \frac{1}{\left| -\frac{19}{12} \right|} = \frac{12}{19} \] ### Final Answer The equation of the parabola is: \[ 19x^2 - 79x + 12y = 48 \] And the length of the latus rectum is: \[ \frac{12}{19} \]
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