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The condition that the parabolas y^2=4c(...

The condition that the parabolas `y^2=4c(x-d)` and `y^2=4ax` have a common normal other than X-axis `(agt0,cgt0)` is

A

`2alt2c+d`

B

`2clt2a+d`

C

`2dlt2a+c`

D

`2dlt2c+a`

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The correct Answer is:
To solve the problem of finding the condition that the parabolas \( y^2 = 4c(x - d) \) and \( y^2 = 4ax \) have a common normal other than the x-axis, we will follow these steps: ### Step 1: Write the normal equations for both parabolas 1. **For the parabola \( y^2 = 4ax \)**: - The general normal equation in terms of slope \( m \) is given by: \[ y = mx - 2am - am^3 \] 2. **For the parabola \( y^2 = 4c(x - d) \)**: - The equation can be rewritten as \( y^2 = 4c(x - d) \). The normal equation becomes: \[ y = m(x - d) - 2cm - cm^3 \] - Simplifying this gives: \[ y = mx - md - 2cm - cm^3 \] ### Step 2: Set the slopes equal Since both parabolas have a common normal, the slopes of their normals must be equal. Thus, we equate the two normal equations: \[ mx - 2am - am^3 = mx - md - 2cm - cm^3 \] ### Step 3: Eliminate \( mx \) and equate the constant terms By eliminating \( mx \) from both sides, we get: \[ -2am - am^3 = -md - 2cm - cm^3 \] Rearranging gives: \[ 2am + md + 2cm + am^3 + cm^3 = 0 \] ### Step 4: Factor out common terms We can factor out \( m \) from the terms involving \( m \): \[ m(2a + c + am^2 + cm^2) + md = 0 \] ### Step 5: Solve for \( m \) Since \( m \neq 0 \) (we are looking for a normal other than the x-axis), we can divide by \( m \): \[ 2a + c + am^2 + cm^2 + d = 0 \] ### Step 6: Rearranging the equation Rearranging gives us: \[ am^2 + cm^2 + 2a + c + d = 0 \] ### Step 7: Analyze the quadratic in \( m^2 \) This is a quadratic equation in \( m^2 \): \[ (a + c)m^2 + (2a + d + c) = 0 \] For this quadratic to have real solutions, the discriminant must be non-negative: \[ (2a + d + c)^2 - 4a(0) \geq 0 \] ### Step 8: Condition for common normal Thus, we require: \[ 2a + d + 2c \geq 0 \] ### Final Condition After analyzing the conditions, we find that the condition for the parabolas to have a common normal other than the x-axis is: \[ 2a < d + 2c \]
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ARIHANT MATHS ENGLISH-PARABOLA-Exercise (Questions Asked In Previous 13 Years Exam)
  1. The condition that the parabolas y^2=4c(x-d) and y^2=4ax have a common...

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  2. about to only mathematics

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  3. Let P be the point (1,0) and Q be a point on the locus y^(2)=8x. The l...

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  4. The axis of a parabola is along the line y=x and the distance of its v...

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  5. about to only mathematics

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  6. The locus of the vertex of the family of parabolas y=(a^3x^2)/3+(a^(2x...

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  7. The angle between the tangents to the curve y=x^2-5x+6 at the point (2...

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  8. Consider the circle x^2 + y^2 = 9 and the parabola y^2 = 8x. They inte...

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  9. Consider the circle x^2 + y^2 = 9 and the parabola y^2 = 8x. They inte...

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  10. Find slope of tangent to the curve if equation is x^2 + y^2 = 9

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  11. Statement 1 : The curve y=-(x^2)/2+x+1 is symmetric with respect to th...

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  12. The equation of a tangent to the parabola y^2=""8x""i s""y""=""x""+...

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  13. Consider two curves C1:y^2=4x ; C2=x^2+y^2-6x+1=0. Then, a. C1 and C2 ...

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  14. If a parabola has the origin as its focus and the line x = 2 as the ...

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  15. about to only mathematics

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  16. Let A and B be two distinct points on the parabola y^2=4x. If the ax...

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  17. If two tangents drawn from a point P to the parabola y2 = 4x are at ri...

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  18. about to only mathematics

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  19. about to only mathematics

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  21. about to only mathematics

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