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If the vertex and focus of a parabola ar...

If the vertex and focus of a parabola are `(3,3)` and `(-3,3)` respectively, then its equation is

A

A. `x^2-6x+24y-63=0`

B

B. `x^2-6x+24y-81=0`

C

C. `y^2-6y+24x-63=0`

D

D.`y^2-6y-24x+81=0`

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The correct Answer is:
To find the equation of the parabola given its vertex and focus, we can follow these steps: ### Step 1: Identify the Vertex and Focus The vertex of the parabola is given as \( V(3, 3) \) and the focus as \( F(-3, 3) \). ### Step 2: Determine the Orientation of the Parabola Since the y-coordinates of the vertex and focus are the same (both are 3), the parabola opens horizontally. The general form for a horizontally opening parabola is: \[ (y - k)^2 = 4p(x - h) \] where \( (h, k) \) is the vertex and \( p \) is the distance from the vertex to the focus. ### Step 3: Calculate the Distance \( p \) The distance \( p \) can be calculated as the distance between the vertex and the focus. Since the vertex is at \( (3, 3) \) and the focus is at \( (-3, 3) \): \[ p = x_{focus} - x_{vertex} = -3 - 3 = -6 \] Thus, \( p = -6 \). ### Step 4: Substitute Values into the Parabola Equation Now we can substitute \( h = 3 \), \( k = 3 \), and \( p = -6 \) into the equation: \[ (y - 3)^2 = 4(-6)(x - 3) \] This simplifies to: \[ (y - 3)^2 = -24(x - 3) \] ### Step 5: Expand the Equation Now we will expand the equation: \[ (y - 3)^2 = -24x + 72 \] Expanding the left side: \[ y^2 - 6y + 9 = -24x + 72 \] ### Step 6: Rearranging the Equation Rearranging gives: \[ y^2 - 6y + 24x + 9 - 72 = 0 \] This simplifies to: \[ y^2 - 6y + 24x - 63 = 0 \] ### Conclusion The equation of the parabola is: \[ y^2 - 6y + 24x - 63 = 0 \]
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ARIHANT MATHS ENGLISH-PARABOLA-Exercise For Session 1
  1. The vertex of the parabola y^2+6x-2y+13=0 is

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  2. If the parabola y^2=4a x\ passes through the point (3,2) then find th...

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  3. Find the value of P such that the vertex of y=x^2+2p x+13 is 4 units a...

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  4. The length of the latusrectum of the parbola whose focus is (3, 3) and...

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  5. If the vertex and focus of a parabola are (3,3) and (-3,3) respectivel...

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  6. If the vertex of the parabola y=x^(2) +x+c lies on x-axis, then the va...

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  7. The parabola having its focus at (3,2) and directrix along the Y-axis ...

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  8. about to only mathematics

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  9. The equation of the latus retum of the parabola x^(2)+4x+2y=0 is

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  10. The focus of the parabola x^2-8x+2y+7=0 is

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  11. The equation of the parabola with the focus (3,0) and directrix x+3=0 ...

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  12. Equation of the parabola whose axis is parallel to Y- axis and which p...

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  13. Find the equation of the parabola whose focus is (5,3) and directrix i...

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  14. about to only mathematics

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  15. Find the vertex , focus, axis , directrix and latusrectum of the parab...

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  16. Find the name of the conic represented by sqrt((x/a))+sqrt((y/b))=1.

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  17. The curve described parametrically by x=t^2+t+1 , and y=t^2-t+1 repres...

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  18. Prove that the equation of the parabola whose vertex and focus are on ...

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  19. Find the equatin to the parabola whose axis is parallel to the y-xis a...

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  20. The equation ax^2+4xy+y^2+ax+3y+2=0 represents a parabola. Find the va...

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