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Find the equation of the parabola whose focus is (5,3) and directrix is the line 3x-4y+1=0.

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To find the equation of the parabola with focus at (5, 3) and directrix given by the line \(3x - 4y + 1 = 0\), we will follow these steps: ### Step 1: Understand the definition of a parabola A parabola is defined as the set of all points \(P\) such that the distance from \(P\) to the focus \(F\) is equal to the perpendicular distance from \(P\) to the directrix \(D\). ### Step 2: Set up the distance equations Let \(P(x, y)\) be a point on the parabola. The distance from \(P\) to the focus \(F(5, 3)\) is given by: \[ PF = \sqrt{(x - 5)^2 + (y - 3)^2} \] The distance from point \(P\) to the directrix \(3x - 4y + 1 = 0\) can be calculated using the formula for the distance from a point to a line: \[ PD = \frac{|3x - 4y + 1|}{\sqrt{3^2 + (-4)^2}} = \frac{|3x - 4y + 1|}{5} \] ### Step 3: Set the distances equal According to the definition of the parabola: \[ \sqrt{(x - 5)^2 + (y - 3)^2} = \frac{|3x - 4y + 1|}{5} \] ### Step 4: Square both sides to eliminate the square root Squaring both sides gives: \[ (x - 5)^2 + (y - 3)^2 = \left(\frac{3x - 4y + 1}{5}\right)^2 \] ### Step 5: Simplify both sides Expanding the left side: \[ (x - 5)^2 + (y - 3)^2 = (x^2 - 10x + 25) + (y^2 - 6y + 9) = x^2 + y^2 - 10x - 6y + 34 \] Expanding the right side: \[ \left(\frac{3x - 4y + 1}{5}\right)^2 = \frac{(3x - 4y + 1)^2}{25} \] Expanding \((3x - 4y + 1)^2\): \[ = 9x^2 - 24xy + 16y^2 + 6x - 8y + 1 \] Thus, \[ \frac{9x^2 - 24xy + 16y^2 + 6x - 8y + 1}{25} \] ### Step 6: Cross-multiply to eliminate the fraction Cross-multiplying gives: \[ 25(x^2 + y^2 - 10x - 6y + 34) = 9x^2 - 24xy + 16y^2 + 6x - 8y + 1 \] ### Step 7: Rearrange the equation Expanding the left side: \[ 25x^2 + 25y^2 - 250x - 150y + 850 = 9x^2 - 24xy + 16y^2 + 6x - 8y + 1 \] Bringing all terms to one side: \[ 25x^2 - 9x^2 + 25y^2 - 16y^2 + 24xy - 250x - 6x - 150y + 8y + 850 - 1 = 0 \] This simplifies to: \[ 16x^2 + 9y^2 + 24xy - 256x - 142y + 849 = 0 \] ### Final Equation Thus, the equation of the parabola is: \[ 16x^2 + 9y^2 + 24xy - 256x - 142y + 849 = 0 \]
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ARIHANT MATHS ENGLISH-PARABOLA-Exercise For Session 1
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  2. If the parabola y^2=4a x\ passes through the point (3,2) then find th...

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  3. Find the value of P such that the vertex of y=x^2+2p x+13 is 4 units a...

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  4. The length of the latusrectum of the parbola whose focus is (3, 3) and...

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  5. If the vertex and focus of a parabola are (3,3) and (-3,3) respectivel...

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  6. If the vertex of the parabola y=x^(2) +x+c lies on x-axis, then the va...

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  7. The parabola having its focus at (3,2) and directrix along the Y-axis ...

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  8. about to only mathematics

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  9. The equation of the latus retum of the parabola x^(2)+4x+2y=0 is

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  10. The focus of the parabola x^2-8x+2y+7=0 is

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  11. The equation of the parabola with the focus (3,0) and directrix x+3=0 ...

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  12. Equation of the parabola whose axis is parallel to Y- axis and which p...

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  13. Find the equation of the parabola whose focus is (5,3) and directrix i...

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  14. about to only mathematics

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  15. Find the vertex , focus, axis , directrix and latusrectum of the parab...

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  16. Find the name of the conic represented by sqrt((x/a))+sqrt((y/b))=1.

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  17. The curve described parametrically by x=t^2+t+1 , and y=t^2-t+1 repres...

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  18. Prove that the equation of the parabola whose vertex and focus are on ...

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  19. Find the equatin to the parabola whose axis is parallel to the y-xis a...

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  20. The equation ax^2+4xy+y^2+ax+3y+2=0 represents a parabola. Find the va...

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