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The diameter of the parabola y^2=6x corr...

The diameter of the parabola `y^2=6x` corresponding to the system of parallel chords 3x-y+c=0 is

A

(a)y-1=0

B

(b)y-2=0

C

(c)y+1=0

D

(d)y+2=0

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The correct Answer is:
To solve the problem of finding the diameter of the parabola \( y^2 = 6x \) corresponding to the system of parallel chords given by the equation \( 3x - y + c = 0 \), we can follow these steps: ### Step 1: Identify the parabola and its properties The given parabola is \( y^2 = 6x \). This is a standard form of a parabola that opens to the right. The vertex of this parabola is at the origin (0, 0). ### Step 2: Determine the slope of the chords The equation of the parallel chords is given as \( 3x - y + c = 0 \). We can rearrange this to find the slope: \[ y = 3x + c \] The slope of these lines is 3. ### Step 3: Find the midpoint of the chords Let \( (h, k) \) be the midpoint of the chord of the parabola. The equation of the chord of contact for a point \( (h, k) \) on the parabola is given by: \[ T = S_1 \] where \( T \) is the equation of the chord of contact, and \( S_1 \) is the equation of the parabola evaluated at the point \( (h, k) \). For the parabola \( y^2 = 6x \), we have: \[ S_1 = k^2 = 6h \] ### Step 4: Write the equation of the chord of contact The chord of contact can also be expressed as: \[ k y = 3x + h \] Substituting \( k = 3 \) (the slope of the chords) into the equation gives: \[ y = 3x + h \] ### Step 5: Equate the slopes Since the slopes of the chord of contact and the given lines must be equal, we have: \[ \frac{3}{k} = -\frac{1}{3} \] This gives: \[ k = 1 \] ### Step 6: Find the locus of the midpoint Now, substituting \( k = 1 \) into the equation of the chord gives us: \[ y - k = 0 \implies y - 1 = 0 \] This means the locus of the midpoints of the chords is the line \( y = 1 \). ### Step 7: Determine the diameter of the parabola The diameter of the parabola corresponds to the distance between the points where the line \( y = 1 \) intersects the parabola. To find these points, we substitute \( y = 1 \) into the parabola's equation: \[ 1^2 = 6x \implies 1 = 6x \implies x = \frac{1}{6} \] Thus, the points of intersection are \( \left( \frac{1}{6}, 1 \right) \) and the diameter is the distance across the parabola at this line. ### Step 8: Conclusion The diameter of the parabola corresponding to the line \( y = 1 \) is simply the horizontal distance across the parabola at that height, which is determined by the points of intersection. ### Final Answer The diameter of the parabola corresponding to the system of parallel chords is \( 1 \). ---
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ARIHANT MATHS ENGLISH-PARABOLA-Exercise For Session 2
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  7. The ordinates of points P and Q on the parabola y^2=12x are in the rat...

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  8. The normals at P, Q, R on the parabola y^2 = 4ax meet in a point on th...

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  9. Three normals are drawn from (2lamda,0) to the parabola y^2=4x .Show t...

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  10. If m1,m2 are the slopes of the two tangents that are drawn from (2,3) ...

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  11. Find the angle between the tangents drawn from the origin to the pa...

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  12. If (a , b) is the midpoint of a chord passing through the vertex of th...

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  13. The diameter of the parabola y^2=6x corresponding to the system of par...

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  14. Tangents are drawn from the point (-1, 2) to the parabola y^2 =4x The ...

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  15. for parabola x^2+y^2+2xy−6x−2y+3=0, the focus is.

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  16. Find the locus of the middle points of the chords of the parabola y^2=...

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  17. A ray of light moving parallel to the x-axis gets reflected form a ...

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  18. The locus of the point of intersection of the tangents to the parabola...

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