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Find dy/dx if x^2-ay+3=0...

Find `dy/dx if x^2-ay+3=0`

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To find \(\frac{dy}{dx}\) for the equation \(x^2 - ay + 3 = 0\), we will follow these steps: ### Step 1: Differentiate the equation with respect to \(x\) We start with the given equation: \[ x^2 - ay + 3 = 0 \] Differentiating both sides with respect to \(x\), we apply the differentiation rules: - The derivative of \(x^2\) is \(2x\). - The derivative of \(-ay\) (where \(a\) is a constant) is \(-a \frac{dy}{dx}\). - The derivative of a constant (3) is 0. Thus, we have: \[ \frac{d}{dx}(x^2) - \frac{d}{dx}(ay) + \frac{d}{dx}(3) = 0 \] This simplifies to: \[ 2x - a \frac{dy}{dx} + 0 = 0 \] ### Step 2: Rearrange the equation Now, we can rearrange the equation to isolate \(\frac{dy}{dx}\): \[ 2x - a \frac{dy}{dx} = 0 \] Adding \(a \frac{dy}{dx}\) to both sides gives: \[ 2x = a \frac{dy}{dx} \] ### Step 3: Solve for \(\frac{dy}{dx}\) To find \(\frac{dy}{dx}\), we divide both sides by \(a\): \[ \frac{dy}{dx} = \frac{2x}{a} \] ### Final Result Thus, the derivative \(\frac{dy}{dx}\) is: \[ \frac{dy}{dx} = \frac{2x}{a} \] ---
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