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The axis of a parabola is along the line y=x and the distance of its vertex and focus from origin are `sqrt(2)` and `2sqrt(2)`, respectively. If vertex and focus both lie in the first quadrant, then find equation of the parabola.

A

`(x+y)^2=(x-y-2)`

B

`(x-y)^2=(x+y+2)`

C

`(x-y)^2=4(x+y-2)`

D

`(x-y)^2=8(x+y-2)`

Text Solution

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The correct Answer is:
D
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