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The function `g(x) = {{:(x+b",",x lt 0),(cos x",",x ge 0):}` can be made differentiable at x = 0

A

(a) if b is equal to zero

B

(b) if b is not equal to zero

C

(c) if b takes any real value

D

(d) for no value of b

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The correct Answer is:
To determine the value of \( b \) for which the function \[ g(x) = \begin{cases} x + b & \text{if } x < 0 \\ \cos x & \text{if } x \geq 0 \end{cases} \] can be made differentiable at \( x = 0 \), we need to ensure that both the function is continuous at \( x = 0 \) and that the left-hand derivative equals the right-hand derivative at that point. ### Step 1: Check Continuity at \( x = 0 \) For \( g(x) \) to be continuous at \( x = 0 \), we need: \[ \lim_{x \to 0^-} g(x) = \lim_{x \to 0^+} g(x) = g(0) \] Calculating \( g(0) \): \[ g(0) = \cos(0) = 1 \] Now, calculate the left-hand limit: \[ \lim_{x \to 0^-} g(x) = \lim_{x \to 0^-} (x + b) = 0 + b = b \] Now, calculate the right-hand limit: \[ \lim_{x \to 0^+} g(x) = \lim_{x \to 0^+} \cos x = \cos(0) = 1 \] Setting the left-hand limit equal to the right-hand limit for continuity: \[ b = 1 \] ### Step 2: Check Differentiability at \( x = 0 \) Next, we need to check the derivatives from both sides. **Left-hand derivative:** \[ g'(x) = 1 \quad \text{for } x < 0 \] Thus, the left-hand derivative at \( x = 0 \) is: \[ \lim_{x \to 0^-} g'(x) = 1 \] **Right-hand derivative:** \[ g'(x) = -\sin x \quad \text{for } x \geq 0 \] Thus, the right-hand derivative at \( x = 0 \) is: \[ \lim_{x \to 0^+} g'(x) = -\sin(0) = 0 \] ### Step 3: Compare the Left-hand and Right-hand Derivatives For \( g(x) \) to be differentiable at \( x = 0 \): \[ \lim_{x \to 0^-} g'(x) = \lim_{x \to 0^+} g'(x) \] This means: \[ 1 \neq 0 \] Since the left-hand derivative (1) does not equal the right-hand derivative (0), the function is not differentiable at \( x = 0 \) for any value of \( b \). ### Conclusion Thus, the function \( g(x) \) can be made differentiable at \( x = 0 \) for **no value of \( b \)**. ### Final Answer The answer is: **For no value of \( b \)**. ---
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