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Consider two functions f(x)=1+e^(cot^(2)...

Consider two functions `f(x)=1+e^(cot^(2)x) " and " g(x)=sqrt(2abs(sinx)-1)+(1-cos2x)/(1+sin^(4)x).`
`bb"Statement I"` The solutions of the equation f(x)=g(x) is given by `x=(2n+1)pi/2, forall "n" in I.`
`bb"Statement II"` If `f(x) ge k " and " g(x) le k` (where k `in` R), then solutions of the equation f(x)=g(x) is the solution corresponding to the equation f(x)=k.

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