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f(x)=log(e)x, g(x)=1/(log(x)e) . Identic...

`f(x)=log_(e)x, g(x)=1/(log_(x)e)` . Identical function or not?

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To determine whether the functions \( f(x) = \log_e x \) and \( g(x) = \frac{1}{\log_x e} \) are identical, we need to check three conditions: 1. The domains of both functions must be equal. 2. The ranges of both functions must be equal. 3. For all \( x \) in the common domain, \( f(x) \) must equal \( g(x) \). Let's analyze these functions step by step. ### Step 1: Determine the domain of \( f(x) \) The function \( f(x) = \log_e x \) is defined for: - \( x > 0 \) Thus, the domain of \( f(x) \) is: \[ \text{Domain of } f = (0, \infty) \] ### Step 2: Determine the domain of \( g(x) \) The function \( g(x) = \frac{1}{\log_x e} \) is defined when: - \( \log_x e \neq 0 \) - \( x > 0 \) - \( x \neq 1 \) (since the logarithm is undefined at this point) Thus, the domain of \( g(x) \) is: \[ \text{Domain of } g = (0, 1) \cup (1, \infty) \] ### Step 3: Compare the domains From the above steps, we see: - Domain of \( f = (0, \infty) \) - Domain of \( g = (0, 1) \cup (1, \infty) \) Since the domains are not equal (specifically, \( g(x) \) is undefined at \( x = 1 \)), we conclude that the first condition is not satisfied. ### Step 4: Conclusion Since the domains of \( f \) and \( g \) are not equal, we can conclude that the functions are not identical. ### Final Answer The functions \( f(x) \) and \( g(x) \) are **not identical**. ---
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