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The graph of the function, cos x cos (x ...

The graph of the function, `cos x cos (x +2) -cos^2 (x+1)` is

A

a straight line passing through `(0-sin^(2)1)` with slope 2

B

a straight line passing through (0,0)

C

a parabola with vertex `(1-sin^(2)1)`

D

a straight line passing through the point `(pi/2,-sin^(2)1)` are parallel to the X-axis

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AI Generated Solution

The correct Answer is:
To find the graph of the function \( y = \cos x \cos(x + 2) - \cos^2(x + 1) \), we will simplify the expression step by step and analyze its properties. ### Step 1: Write the function Start with the given function: \[ y = \cos x \cos(x + 2) - \cos^2(x + 1) \] ### Step 2: Use trigonometric identities We can use the product-to-sum identities to simplify \( \cos x \cos(x + 2) \): \[ \cos x \cos(x + 2) = \frac{1}{2} \left( \cos(2) + \cos(2x + 2) \right) \] Thus, we can rewrite \( y \): \[ y = \frac{1}{2} \left( \cos(2) + \cos(2x + 2) \right) - \cos^2(x + 1) \] ### Step 3: Expand \( \cos^2(x + 1) \) Using the identity \( \cos^2 A = \frac{1 + \cos(2A)}{2} \), we can expand \( \cos^2(x + 1) \): \[ \cos^2(x + 1) = \frac{1 + \cos(2(x + 1))}{2} = \frac{1 + \cos(2x + 2)}{2} \] Substituting this back into our expression for \( y \): \[ y = \frac{1}{2} \left( \cos(2) + \cos(2x + 2) \right) - \frac{1 + \cos(2x + 2)}{2} \] ### Step 4: Combine terms Now, combine the terms: \[ y = \frac{1}{2} \cos(2) + \frac{1}{2} \cos(2x + 2) - \frac{1}{2} - \frac{1}{2} \cos(2x + 2) \] The \( \cos(2x + 2) \) terms cancel out: \[ y = \frac{1}{2} \cos(2) - \frac{1}{2} \] ### Step 5: Simplify further This can be simplified to: \[ y = \frac{1}{2} (\cos(2) - 1) \] Since \( \cos(2) \) is a constant, \( y \) is a constant value. ### Step 6: Conclusion about the graph Since \( y \) is a constant, the graph of this function is a horizontal line. The specific value of \( y \) is \( \frac{1}{2} (\cos(2) - 1) \), which is a constant value. ### Final Answer The graph of the function is a straight line parallel to the x-axis.
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