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Prove that the circles x^(2) +y^(2) - 4x...

Prove that the circles `x^(2) +y^(2) - 4x + 6y + 8 = 0` and `x^(2) + y^(2) - 10x - 6y + 14 = 0` touch at the point (3,-1)

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The correct Answer is:
Hence, the given circles touch at (3,-1).
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