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The circle x^2+y^2-4x-4y+4=0 is inscribe...

The circle `x^2+y^2-4x-4y+4=0` is inscribed in a triangle which has two of its sides along the coordinate axes. The locus of the circumcenter of the triangle is `x+y-x y+k(x^2+y^2)^(1/2)=0` . Find `kdot`

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The correct Answer is:
Hence, the required value of k is 1.
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