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The minimum radius of the circle which c...

The minimum radius of the circle which contains the three circles, `x^(2)+y^(2)-4y-5=0,x^(2)+y^(2)+12x+4y+31=0` and `x^(2)+y^(2)+6x+12y+36=0` is

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The correct Answer is:
`(x+(31)/(18))^(2)+(y+(23)/(12))^(2)=(3+(5)/(sqrt36)sqrt949)^(2)`
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