Home
Class 12
MATHS
The normal at the point (3,4) on a circl...

The normal at the point (3,4) on a circle cuts the circle at the poins `(-1,-2)`. Then the equation of the circle is

A

`x^(2)+y^(2)+2x-2y-13=0`

B

`x^(2)+y^(2)-2x-2y-11=0`

C

`x^(2)+y^(2)-2x+2y+12=0`

D

`x^(2)+y^(2)+2x-2y+14=0`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • CIRCLE

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 5|16 Videos

  • CIRCLE

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 6|16 Videos

  • CIRCLE

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 3|16 Videos

  • BIONOMIAL THEOREM

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|21 Videos

  • COMPLEX NUMBERS

    ARIHANT MATHS ENGLISH|Exercise Complex Number Exercise 8|2 Videos

Similar Questions

Explore conceptually related problems

The normal at the point (3, 4) on a circle cuts the circle at the point (-1,-2). Then the equation of the circle is

The vertex of the parabola y^2 = 8x is at the centre of a circle and the parabola cuts the circle at the ends of itslatus rectum. Then the equation of the circle is

A foot of the normal from the point (4, 3) to a circle is (2, 1) and a diameter of the circle has the equation 2x -y -2 =0 . Then the equation of the circle is:

The equation of radical axis of two circles is x + y = 1 . One of the circles has the ends ofa diameter at the points (1, -3) and (4, 1) and the other passes through the point (1, 2).Find the equations of these circles.

The point on a circle nearest to the point P(2,1) is at a distance of 4 units and the farthest point is (6, 5). Then find the equation of the circle.

The point on a circle nearest to the point P(2,1) is at a distance of 4 units and the farthest point is (6, 5). Then find the equation of the circle.

The line 2x - y + 1 = 0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y = 4. The radius of the circle is :

A circle having its centre in the first quadrant touches the y-axis at the point (0,2) and passes through the point (1,0). Find the equation of the circle

Line 2x+3y+1=0 is a tangent to the circle at (1,-1). This circle is orthogonal to a circle which is drawn having diameter as a line segment with end points (0, -1) and (-2, 3). Then the equation of the circle is

The co-ordinates of the end points of a diameter of a circle are (0,0) and (4,4). The equation of the circle is :