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If r1a n dr2 are the radii of the smalle...

If `r_1a n dr_2` are the radii of the smallest and the largest circles, respectively, which pass though (5, 6) and touch the circle `(x-2)^2+y^2=4,` then `r_1r_2` is (a) `4/(41)` (b) `(41)/4` `5/(41)` (d) `(41)/6`

A

`(4)/(41)`

B

`(41)/(4)`

C

`(5)/(41)`

D

`(41)/(5)`

Text Solution

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The correct Answer is:
B
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