Home
Class 12
MATHS
Let P be a point on the circle x^(2)+y^(...

Let P be a point on the circle `x^(2)+y^(2)=9` , Q a point on the line `7x+y+3=0`, and the perpendicular bisector of PQ be the line `x-y+1=0`. Then the coordinates of P are

A

(3,0)

B

`((72)/(25),-(21)/(25))`

C

(0,3)

D

`(-(72)/(25),(21)/(25))`

Text Solution

Verified by Experts

The correct Answer is:
A, D
Promotional Banner

Topper's Solved these Questions

  • CIRCLE

    ARIHANT MATHS ENGLISH|Exercise Exercise (Passage Based Questions)|21 Videos
  • CIRCLE

    ARIHANT MATHS ENGLISH|Exercise Exercise (Single Integer Answer Type Questions)|9 Videos
  • CIRCLE

    ARIHANT MATHS ENGLISH|Exercise Exercise (Single Option Correct Type Questions)|30 Videos
  • BIONOMIAL THEOREM

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|21 Videos
  • COMPLEX NUMBERS

    ARIHANT MATHS ENGLISH|Exercise Complex Number Exercise 8|2 Videos

Similar Questions

Explore conceptually related problems

Let P be a point on the circle x^2+y^2=9,Q a point on the line 7x+y+3=0 , and the perpendicular bisector of P Q be the line x-y+1=0 . Then the coordinates of P are (0,-3) (b) (0,3) ((72)/(25),(21)/(35)) (d) (-(72)/(25),(21)/(25))

P is a point on the circle x^2+y^2=9 Q is a point on the line 7x+y+3=0 . The perpendicular bisector of PQ is x-y+1=0 . Then the coordinates of P are:

The point A (2,7) lies on the perpendicular bisector of the line segment joining the points P (5,-3) and Q(0,-4).

P is a variable point on the line L=0 . Tangents are drawn to the circles x^(2)+y^(2)=4 from P to touch it at Q and R. The parallelogram PQSR is completed. If P -=(3,4) , then the coordinates of S are

Tangents drawn to circle (x-1)^2 +(y -1)^2= 5 at point P meets the line 2x +y+ 6= 0 at Q on the x axis. Length PQ is equal to

If P is the point (2,1,6) find the point Q such that PQ is perpendicular to the plane x+y-2z=3 and the mid point of PQ lies on it.

If the line x + y = 1 touches the parabola y^2-y + x = 0 , then the coordinates of the point of contact are:

From any point P on the line x = 2y perpendicular is drawn on y = x. Let foot of perpendicular is Q. Find the locus of mid point of PQ.

Point P(0,2) is the point of intersection of Y-axis and perpendicular bisector of line segment joining the points A(-1,1) and B(3,3).

P and Q are any two points on the circle x^2+y^2= 4 such that PQ is a diameter. If alpha and beta are the lengths of perpendiculars from P and Q on x + y = 1 then the maximum value of alphabeta is