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Equation of the circumcircle of a triang...

Equation of the circumcircle of a triangle formed by the lines `L_(1)=0,L_(2)=0andL_(3)=0` can be written as `L_(1)L_(2)+lamdaL_(2)L_(3)+muL_(3)L_(1)=0`, where `lamdaandmu` are such that coefficient of `x^(2)` =coefficient of `y^(2)` and coefficient of xy=0.
If `L_(1)L_(2)+lamdaL_(2)L_(3)+muL_(3)L_(1)=0` is such that `mu=0andlamda` is non-zero, then it represents

A

a parabola

B

a pair of straight lines

C

a circle

D

an ellipse

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The correct Answer is:
To solve the problem, we need to analyze the given equation of the circumcircle of a triangle formed by the lines \( L_1 = 0 \), \( L_2 = 0 \), and \( L_3 = 0 \). The equation can be expressed as: \[ L_1 L_2 + \lambda L_2 L_3 + \mu L_3 L_1 = 0 \] where \( \lambda \) and \( \mu \) are coefficients that we need to determine under the conditions that the coefficient of \( x^2 \) equals the coefficient of \( y^2 \) and the coefficient of \( xy = 0 \). ### Step 1: Understanding the Lines The lines \( L_1 = 0 \), \( L_2 = 0 \), and \( L_3 = 0 \) represent three lines in the Cartesian plane. The intersection points of these lines will form the vertices of the triangle. ### Step 2: Setting Up the Equation The circumcircle of the triangle can be represented by the equation: \[ L_1 L_2 + \lambda L_2 L_3 + \mu L_3 L_1 = 0 \] ### Step 3: Analyzing the Coefficients We know that: - The coefficient of \( x^2 \) is equal to the coefficient of \( y^2 \). - The coefficient of \( xy = 0 \). This means we need to ensure that the terms involving \( \lambda \) and \( \mu \) satisfy these conditions. ### Step 4: Substituting Values Given that \( \mu = 0 \) and \( \lambda \) is non-zero, we can simplify the equation to: \[ L_1 L_2 + \lambda L_2 L_3 = 0 \] ### Step 5: Evaluating the Equation Now, substituting \( L_1, L_2, L_3 \) with their respective values (which are functions of \( x \) and \( y \)), we can analyze the behavior of the equation. ### Step 6: Conclusion Since \( L_1, L_2, L_3 \) represent the lines that form the triangle, and the equation represents a curve, we can conclude that the equation represents a curve passing through the points of intersection of the lines \( L_1 = 0 \), \( L_2 = 0 \), and \( L_3 = 0 \). ### Final Answer Thus, the final answer is that the equation represents a curve passing through the points of intersection of the lines \( L_1 = 0 \), \( L_2 = 0 \), and \( L_3 = 0 \). ---
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ARIHANT MATHS ENGLISH-CIRCLE -Exercise (Passage Based Questions)
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  3. P is a variable point on the line L=0 . Tangents are drawn to the circ...

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  4. P is a variable point on the line L=0. Tangents are drawn to the circl...

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  5. P is a variable point on the line L=0 . Tangents are drawn to the circ...

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  6. Equation of the circumcircle of a triangle formed by the lines L(1)=0,...

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  7. Equation of the circumcircle of a triangle formed by the lines L(1)=0,...

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  8. Equation of the circumcircle of a triangle formed by the lines L(1)=0,...

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  9. Give two circles intersecting orthogonally having the length of common...

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  10. Given two circles intersecting orthogonally having the length of commo...

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  11. Given two circles intersecting orthogonally having the length of commo...

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  13. Consider the two circles C(1):x^(2)+y^(2)=a^(2)andC(2):x^(2)+y^(2)=b^(...

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  14. Consider the two circles C(1):x^(2)+y^(2)=a^(2)andC(2):x^(2)+y^(2)=b^(...

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  15. Two variable chords AB and BC of a circle x^(2)+y^(2)=a^(2) are such t...

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  16. Two variable chords AB and BC of a circle x^(2)+y^(2)=a^(2) are such t...

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  17. Two variable chords AB and BC of a circle x^(2)+y^(2)=a^(2) are such t...

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