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Find the equation of the circle passing ...

Find the equation of the circle passing through `(1,0)a n d(0,1)` and having the smallest possible radius.

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The correct Answer is:
B
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The equation of the circle passing through (1, 0) and (0, 1) and having smallest possible radius is : (A) 2x^2 + y^2 - 2x-y=0 (B) x^2 + 2y^2 - x - 2y = 0 (C) x^2 = y^2 - x - y = 0 (D) x^2 + y^2 + x + y = 0

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Knowledge Check

  • The equation of the smallest circle passing through the point (1,0) and (0,1) is

    A
    A. ` x^(2) + y^(2) + x + y = 0 `
    B
    B. ` x^(2) + y^(2) - x - y = 0 `
    C
    C. ` x^(2) + y^(2) - x - y + 2 = 0 `
    D
    D. ` x^(2) + y^(2) - x - y - 1 = 0 `

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