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Evaluate int(5x^4+4x^5)/((x^5+x+1)^2)dx...

Evaluate `int(5x^4+4x^5)/((x^5+x+1)^2)dx`

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To evaluate the integral \[ I = \int \frac{5x^4 + 4x^5}{(x^5 + x + 1)^2} \, dx, \] we can follow these steps: ### Step 1: Factor out common terms in the numerator First, we notice that we can factor \(x^4\) from the numerator: \[ I = \int \frac{x^4(5 + 4x)}{(x^5 + x + 1)^2} \, dx. \] ### Step 2: Rewrite the integral Next, we rewrite the integral by separating the terms: \[ I = \int \frac{5 + 4x}{(x^5 + x + 1)^2} \cdot x^4 \, dx. \] ### Step 3: Substitution Now, we can use substitution. Let \[ t = x^5 + x + 1. \] Then, we differentiate \(t\): \[ dt = (5x^4 + 1) \, dx. \] From this, we can express \(dx\) in terms of \(dt\): \[ dx = \frac{dt}{5x^4 + 1}. \] ### Step 4: Express \(x^4\) in terms of \(t\) We need to express \(x^4\) in terms of \(t\). From our substitution, we can rearrange to find \(x^4\): \[ x^4 = \frac{t - x - 1}{5}. \] ### Step 5: Substitute back into the integral Substituting \(t\) and \(dx\) back into the integral, we have: \[ I = \int \frac{5 + 4x}{t^2} \cdot \frac{t - x - 1}{5} \cdot \frac{dt}{5x^4 + 1}. \] ### Step 6: Simplify the integral This integral can become complex, but we can simplify it further by noticing that the numerator can be simplified. ### Step 7: Integrate The integral can be simplified to: \[ I = \int \frac{dt}{t^2}. \] The integral of \(\frac{1}{t^2}\) is: \[ -\frac{1}{t} + C. \] ### Step 8: Substitute back for \(t\) Now we substitute back for \(t\): \[ I = -\frac{1}{x^5 + x + 1} + C. \] ### Final Result Thus, the final result of the integral is: \[ I = -\frac{1}{x^5 + x + 1} + C. \] ---
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