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The area enclosed by the curve `y=sinx+cosxa n dy=|cosx-sinx|` over the interval `[0,pi/2]` is `(a)4(sqrt(2)-2)` (b) `2sqrt(2)` (`sqrt(2)` -1) `(c)2(sqrt(2)` +1) (d) `2sqrt(2)(sqrt(2)+1)`

A

`4(sqrt(2)-1)`

B

`2sqrt(2)(sqrt(2)-1)`

C

`2(sqrt(2)+1)`

D

`2sqrt(2)(sqrt(2)+1)`

Text Solution

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The correct Answer is:
B
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