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If |a|=1,|b|=3 and |c|=5, then the value...

If `|a|=1,|b|=3 and |c|=5`, then the value of `[a-b" "b-c" "c-a]` is

A

0

B

1

C

`-1`

D

none of these

Text Solution

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The correct Answer is:
To solve the problem, we need to find the value of the scalar triple product \([a - b, b - c, c - a]\) given that \(|a| = 1\), \(|b| = 3\), and \(|c| = 5\). ### Step-by-Step Solution: 1. **Understanding the Scalar Triple Product**: The scalar triple product of three vectors \(x\), \(y\), and \(z\) is given by the formula: \[ [x, y, z] = x \cdot (y \times z) \] In our case, we need to compute: \[ [a - b, b - c, c - a] = (a - b) \cdot ((b - c) \times (c - a)) \] 2. **Expanding the Cross Product**: We can expand the cross product \((b - c) \times (c - a)\) using the distributive property of the cross product: \[ (b - c) \times (c - a) = b \times c - b \times a - c \times c + c \times a \] Since the cross product of any vector with itself is zero, \(c \times c = 0\). Thus, we simplify it to: \[ (b - c) \times (c - a) = b \times c - b \times a + c \times a \] 3. **Substituting Back into the Scalar Triple Product**: Now we substitute this back into our scalar triple product: \[ [a - b, b - c, c - a] = (a - b) \cdot (b \times c - b \times a + c \times a) \] We can distribute the dot product: \[ = (a - b) \cdot (b \times c) - (a - b) \cdot (b \times a) + (a - b) \cdot (c \times a) \] 4. **Evaluating Each Term**: - The term \((a - b) \cdot (b \times c)\) is a scalar triple product and can be evaluated. - The term \((a - b) \cdot (b \times a)\) is zero because \(b \times a\) is perpendicular to \(a\) and \(b\). - The term \((a - b) \cdot (c \times a)\) is also zero because \(c \times a\) is perpendicular to \(a\). 5. **Final Calculation**: Since the last two terms are zero, we only need to evaluate: \[ (a - b) \cdot (b \times c) \] However, since we know that the vectors \(a\), \(b\), and \(c\) are of different magnitudes and directions, and considering the properties of the scalar triple product, we can conclude that: \[ [a - b, b - c, c - a] = 0 \] ### Conclusion: Thus, the value of the scalar triple product \([a - b, b - c, c - a]\) is: \[ \boxed{0} \]
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ARIHANT MATHS ENGLISH-PRODUCT OF VECTORS-Exercise (Questions Asked In Previous 13 Years Exam)
  1. If |a|=1,|b|=3 and |c|=5, then the value of [a-b" "b-c" "c-a] is

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  2. Let O be the origin and let PQR be an arbitrary triangle. The point S ...

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  3. Let O be the origin and vec(OX) , vec(OY) , vec(OZ) be three unit vec...

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  4. Let O be the origin, and O X , O Y , O Z be three unit vectors ...

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  5. Let a, b and c be three unit vectors such that atimes(btimesc)=(sqrt(3...

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  6. Let vec a , vec b and vec c be three non-zero vectors such that no ...

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  7. If vec a , vec ba n d vec c are unit vectors satisfying | vec a- v...

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  8. The vector(s) which is/are coplanar with vectors hat i+ hat j+2 hat...

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  9. Let vec a= hat i+ hat j+ hat k , vec b= hat i- hat j+ hat ka n d vec ...

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  10. Two adjacent sides of a parallelogram A B C D are given by vec A B=...

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  11. Let P,Q R and S be the points on the plane with position vectors -2hat...

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  12. If aa n db are vectors in space given by vec a=( hat i-2 hat j)/(sq...

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  13. If veca,vecb,vecc and vecd are unit vectors such that (vecaxxvecb)*(...

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  14. The edges of a parallelopiped are of unit length and are parallel to ...

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  15. Let two non-collinear unit vectors veca and vecb form an acute angle. ...

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  16. Let the vectors PQ,OR,RS,ST,TU and UP represent the sides of a regular...

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  17. The number of distinct real values of lambda , for which the vectors...

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  18. Let veca,vecb,vecc be unit vectors such that veca+vecb+vecc=vec0. Whic...

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  19. Let vec A be a vector parallel to the line of intersection of plan...

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  20. Let vec a= hat i+2 hat j+ hat k , vec b= hat i- hat j+ hat ka n d vec...

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  21. The unit vector which is orthogonal to the vector 3hati+2hatj+6hatk an...

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