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In triangle ABC the mid point of the sides AB, BC and AC respectively (l, 0, 0), (0, m, 0) and (0, 0, n). Then, `(AB^2+BC^2+CA^2)/(l^2+m^+n^2)` is equal to

A

`2`

B

`4`

C

`8`

D

`16`

Text Solution

Verified by Experts

The correct Answer is:
C
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