67.2 litre of hydrogen combines with 44.8 litres of nitrogen to form ammonia under specific conditions as :
`N_2(g) + 3H_2(g) rarr 2NH_3(g)`
Calculate the volume of ammonia produced. What is the other substance, if any, that remains in the resultant mixture ?

Explanation

To solve the problem, we need to follow these steps:

### Step 1: Calculate the moles of nitrogen (N₂) and hydrogen (H₂)
Using the formula for moles of gas:
\[ \text{Moles of gas} = \frac{\text{Volume of gas (L)}}{22.4 \text{ L/mol}} \]

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