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Find the total percentage of magnesium i...

Find the total percentage of magnesium in magnesium nitrate crystals `[Mg(NO_(3))_(2).6H_(2)O]`
[Mg=24, N=14, O=16,H-1]

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Relative molecular mass of `Mg(NO_3)_2.6H_2O` = `(24) + (14 xx 2) + (16 xx 6) + (12 xx 1) + (6 xx 16)` = 24 + 28 + 96 + 12 + 96 = 256
Amount of Mg in 256 g of magnesium nitrate is 24 g
`:.` % of Mg in `Mg(NO_3)_2.6H_2O` = `(24)/(256) xx 100` = 9.38%
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