Cards bearing numbers 2, 4, 6, 8, 10, 12, 14, 16, 18 and 20 are kept in a bag. A cord is drawn at random from the bag. Find the probability of getting a card which is
an odd number.

Answer

To solve the problem of finding the probability of drawing a card that bears an odd number from a set of cards, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Sample Space**:
The cards in the bag are numbered: 2, 4, 6, 8, 10, 12, 14, 16, 18, and 20.
Therefore, the sample space \( S \) is:
\[ S = \{2, 4, 6, 8, 10, 12, 14, 16, 18, 20\} \]

2. **Count the Total Number of Outcomes**:
The total number of cards (or outcomes) in the sample space is:
\[ n(S) = 10 \]

3. **Define the Event**:
Let \( E \) be the event of drawing a card that is an odd number.
We need to identify the odd numbers in the sample space.

4. **Identify Favorable Outcomes**:
Looking at the sample space, we see that there are no odd numbers among the cards. The odd numbers are typically 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, but none of these are present in our sample space.
Therefore, the number of favorable outcomes for event \( E \) is:
\[ n(E) = 0 \]

5. **Calculate the Probability**:
The probability of an event is given by the formula:
\[ P(E) = \frac{n(E)}{n(S)} \]
Substituting the values we found:
\[ P(E) = \frac{0}{10} = 0 \]

### Final Answer:
The probability of drawing a card that is an odd number is:
\[ \boxed{0} \]