Smaller area enclosed by the circle x^2...

Smaller area enclosed by the circle `x^2+y^2=4` and the line `x + y = 2` is:

Verified by Experts

The correct Answer is:

`(pi-2)` sq. unit.

Similar Questions

Explore conceptually related problems

Find the area enclosed by the circle x^2+y^2=a^2 .

Area lying in the first quadrant and bounded by the circle x^2+y^2=4 and the lines x= 0 and x= 2 is:

The area enclosed by the curve y^2 +x^4=x^2 is

Find the area enclosed between the circle x^2+y^2=25 and the straight line x+y=5 .

The area bounded by the circle x^(2)+y^(2)=a^(2) and the line x+y=a in the first quadrant is

The area of the region bounded by the circle x^(2)+y^(2)=1 and the line x+y=1 is :

Find the area enclosed between the parabola y^2=4a x and the line y = m x .

Find the area enclosed by the curve y=-x^2 and straight line x+y+2=0.

The area enclosed between the curves y^2=x and y=|x| is

If (-2a,a+1) lies in the interior (smaller region) bounded by the circle x^2+y^2=4 and the parabola y^2=4x , then