The difference between mean and variance of a binomial distribution is 1 and the difference of their squares is 11. Find the distribution.

The sum of mean and variance of a binomial distribution is 15 and the sum of their squares is 117. Determine the distribution.

Find the mean and variance of Binomial Distribution if p=1/2 ,n=1

If the mean and variance of a binomial distribution are 15//4 and 15//16 then the number of trials is

A : If the difference between the mean and variance of a binomial distribution for 5 trials is 5//9 then the distribution o is (2//3+1//3)^(5) R : The binomial distribution with parameters n, p is (q+p)^(n)

If the sum of the mean and variance of a binomial distribution for 6 trials is (10)/(3) , find the binomial distribution.

The mean and variance of a binomial distribution are 4 and 3 respectively. Fix the distribution and find P(X ge 1) .

The sum and the product of the mean and variance of a binomial distribution are 24 and 128 respectively. Find the distribution.

In a binomial distribution the mean is 12 and the standard deviation is sqrt3 . Then the distribution is

In a binomial distribution, n=5, the sum of the mean and variance is 1.8 . Then the distribution is

The mean and variance of a binomial distribution are 4 and 4/3 respectively, find P(X=1)dot