An alternating e.m.f of 220V is applied to a circuit containing a resistor R having resistance of `160Omega` and a capacitor .C. in series. The current is found to lead the supply voltage by an angle `theta= tan^(-1) (3//4)`
Calculate: The capacitive reactance,

Explanation

To find the capacitive reactance \( X_C \) in the given circuit, we can follow these steps:

### Step 1: Identify the given values
- The applied alternating e.m.f (voltage) \( V = 220 \, V \)
- The resistance \( R = 160 \, \Omega \)
- The angle \( \theta = \tan^{-1}\left(\frac{3}{4}\right) \)

### Step 2: Relate the angle to the reactance and resistance
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