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An alternating e.m.f of 220V is applied ...

An alternating e.m.f of 220V is applied to a circuit containing a resistor R having resistance of `160Omega` and a capacitor .C. in series. The current is found to lead the supply voltage by an angle `theta= tan^(-1) (3//4)`
Calculate: Impedance of the circuit

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To solve the problem, we need to calculate the impedance of the circuit containing a resistor and a capacitor in series, given the alternating e.m.f and the phase angle. ### Step-by-Step Solution: 1. **Identify the Given Values**: - Voltage (V) = 220 V (not directly needed for impedance calculation) - Resistance (R) = 160 Ω - Phase angle (θ) = tan^(-1)(3/4) ...
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