Home
Class 12
PHYSICS
In Young.s double slit experiment, the s...

In Young.s double slit experiment, the screen is kept at a distance of 1.2m from the plane of the slits. The two slits are separated by 5mm and illuminated with monochromatic light having wavelength 600 mm. Calculate:
Distance of `10^(th)` bright frings from the centre of the pattern.

Text Solution

AI Generated Solution

To solve the problem of finding the distance of the 10th bright fringe from the center of the pattern in Young's double slit experiment, we will use the formula for the position of bright fringes. The formula is given by: \[ y_n = \frac{n \lambda D}{d} \] where: - \( y_n \) = distance of the nth bright fringe from the center - \( n \) = order of the fringe (in this case, \( n = 10 \)) - \( \lambda \) = wavelength of light ...
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

In Young.s double slit experiment, the screen is kept at a distance of 1.2m from the plane of the slits. The two slits are separated by 5mm and illuminated with monochromatic light having wavelength 600 mm. Calculate: Frings width i.e., fringe separation of the interference pattern.

In Young.s double slit experiment, the screen is kept at a distance of 1.2 m from the plane of the slits. The two slits are separated by 5 mm and illuminated with monochromatic light having wavelength 60 nm. Calculate : (i) Fringe width i.e., fringe separation of the interference pattern. (ii) Distance of 10^(th) bright fringe from the cente of the pattern.

In a Young's double slit experiment , the slits are Kept 2mm apart and the screen is positioned 140 cm away from the plane of the slits. The slits are illuminatedd with light of wavelength 600 nm. Find the distance of the third brite fringe. From the central maximum . in the interface pattern obtained on the screen frings from the central maximum. 3

In a Young's double slit interference experiment the fringe pattern is observed on a screen placed at a distance D from the slits. The slits are separated by a distance d and are illuminated by monochromatic light of wavelength lamda . Find the distance from the central point where the intensity falls to (a) half the maximum, (b) one fourth of the maximum.

In youngs double slit experiment the fringes are formed at a distance of 1m from double slits of sepration 0.12mm .calculate the distance of 4th dark band from the centre of screen ?(wavelength is 12000A).

In the Young's double slit experiment, the spacing between two slits is 0.1mm . If the screen is kept at a distance of 1.0m from the slits and the wavelength of ligth is 5000Å , then the fringe width is

In Young's double slit experiment, the sepcaration between the slits is halved and the distance between the slits and the screen is doubled. The fringe width is

In Young's double slit experiment, the sepcaration between the slits is halved and the distance between the slits and the screen is doubled. The fringe width is

In Young's double slit experiment the fringes are fomred at a distance of 1 m from double slit of separation 0.12 mm calculate. (i). The distance of 3rd dark band from the centre of the screen. (ii). The distance of 3rd bright band from the centre of the screen, Given lamda=6000Å

In young s double slit experiment the fringes are formed at a distance of 1m from double slits of sepration 0.12mm.calculate the distance of 6th bright band from the centre of screen ,given wavelength is 12000A.