When an alternating emf `e= 310 sin (100 pi t) V` is applied to a series LCR circuit, current flowing through it is `i= 5sin (100 pi t+ pi//3)A`.
What is the phase difference between the current and the emf?

Explanation

To find the phase difference between the current and the emf in the given LCR circuit, we can follow these steps:

### Step 1: Write down the equations for emf and current
The given alternating emf and current can be expressed as:
- Emf: \( e = 310 \sin(100 \pi t) \, \text{V} \)
- Current: \( i = 5 \sin(100 \pi t + \frac{\pi}{3}) \, \text{A} \)

### Step 2: Identify the phase angles
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