Home
Class 9
MATHS
State, whether the following numbers are...

State, whether the following numbers are rational or not :
(i) `(2+sqrt(2))^(2)" (ii) "(5+sqrt(5))(5-sqrt(5))`
(iii) `(sqrt(7)/(5sqrt(2)))^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine whether the given numbers are rational or irrational, we will analyze each expression step by step. ### Step 1: Analyze the first expression \((2 + \sqrt{2})^2\) 1. Use the formula for the square of a binomial: \[ (a + b)^2 = a^2 + 2ab + b^2 \] Here, \(a = 2\) and \(b = \sqrt{2}\). 2. Calculate \(a^2\): \[ 2^2 = 4 \] 3. Calculate \(2ab\): \[ 2 \cdot 2 \cdot \sqrt{2} = 4\sqrt{2} \] 4. Calculate \(b^2\): \[ (\sqrt{2})^2 = 2 \] 5. Combine all parts: \[ (2 + \sqrt{2})^2 = 4 + 4\sqrt{2} + 2 = 6 + 4\sqrt{2} \] 6. Since \(\sqrt{2}\) is an irrational number, \(4\sqrt{2}\) is also irrational. Therefore, \(6 + 4\sqrt{2}\) is irrational. ### Conclusion for (i): \((2 + \sqrt{2})^2\) is **irrational**. --- ### Step 2: Analyze the second expression \((5 + \sqrt{5})(5 - \sqrt{5})\) 1. Use the difference of squares formula: \[ (a + b)(a - b) = a^2 - b^2 \] Here, \(a = 5\) and \(b = \sqrt{5}\). 2. Calculate \(a^2\): \[ 5^2 = 25 \] 3. Calculate \(b^2\): \[ (\sqrt{5})^2 = 5 \] 4. Combine the results: \[ (5 + \sqrt{5})(5 - \sqrt{5}) = 25 - 5 = 20 \] 5. Since 20 is an integer, it is a rational number. ### Conclusion for (ii): \((5 + \sqrt{5})(5 - \sqrt{5})\) is **rational**. --- ### Step 3: Analyze the third expression \(\left(\frac{\sqrt{7}}{5\sqrt{2}}\right)^2\) 1. Square the numerator and the denominator: \[ \left(\frac{\sqrt{7}}{5\sqrt{2}}\right)^2 = \frac{(\sqrt{7})^2}{(5\sqrt{2})^2} \] 2. Calculate the numerator: \[ (\sqrt{7})^2 = 7 \] 3. Calculate the denominator: \[ (5\sqrt{2})^2 = 5^2 \cdot (\sqrt{2})^2 = 25 \cdot 2 = 50 \] 4. Combine the results: \[ \frac{7}{50} \] 5. Since \(\frac{7}{50}\) is a fraction where both the numerator and denominator are integers and the denominator is not zero, it is a rational number. ### Conclusion for (iii): \(\left(\frac{\sqrt{7}}{5\sqrt{2}}\right)^2\) is **rational**. --- ### Final Summary: - (i) \((2 + \sqrt{2})^2\) is **irrational**. - (ii) \((5 + \sqrt{5})(5 - \sqrt{5})\) is **rational**. - (iii) \(\left(\frac{\sqrt{7}}{5\sqrt{2}}\right)^2\) is **rational**. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

State, whether the following numbers are rational or not: (sqrt(3)-sqrt(2))^(2)

State, whether the following numbers are rational or not: ((sqrt(7))/(6sqrt(2)))^(2)

State, whether the following numbers are rational or not: (5+sqrt(5)) ( 5- sqrt(5))

Examine, whether the following numbers are rational or irrational: (i) (sqrt(2)+2)^2 (ii) (5+sqrt(5))(5-sqrt(5)) (iii) 6/(2sqrt(3))

Examine whether the following numbers are rational or irrational : (3- sqrt5) ^(2)

Examine, whether the following numbers are rational or irrational: (i) (sqrt(5)-2) (ii) sqrt(23) (iii) sqrt(255)

Examine, whether the following numbers are rational or irrational: (i) sqrt(3)+sqrt(2) (ii) sqrt(3)+sqrt(5) (iii) (sqrt(2)-2)^2

Examine, whether the following numbers are rational or irrational: (i) sqrt(7) (ii) sqrt(4) (iii) 2+sqrt(3)

Examine, whether the following numbers are rational or irrational: (i) (2-sqrt(2))(2+sqrt(2)) (ii) (sqrt(2)+sqrt(3))^2

Simplify : (i) (5+sqrt(5))(5-sqrt(5)) (ii) (3+2sqrt(2))(3-2sqrt(2))