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State, with reason, which of the followi...

State, with reason, which of the following are surds and which are not :
(i) `sqrt(180) " (ii) "root(3)(64)" (iii) "root(3)(25) times root(3)(40)`

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The correct Answer is:
To determine which of the given expressions are surds and which are not, we need to apply the definition of a surd. A surd is an expression that cannot be simplified to remove the root. Specifically, a number is a surd if it is in the form \( \sqrt[n]{x} \) where \( x \) is not a perfect nth power. Let's analyze each part step-by-step: ### Step 1: Analyze \( \sqrt{180} \) 1. **Find the prime factorization of 180**: - \( 180 = 2^2 \times 3^2 \times 5 \) 2. **Check for perfect squares**: - The factors \( 2^2 \) and \( 3^2 \) are perfect squares, but \( 5 \) is not. 3. **Conclusion**: - Since \( \sqrt{180} \) cannot be simplified to a whole number (because of the factor \( 5 \)), it is a surd. ### Step 2: Analyze \( \sqrt[3]{64} \) 1. **Find the prime factorization of 64**: - \( 64 = 4^3 = 2^6 \) 2. **Check for perfect cubes**: - \( 64 \) is a perfect cube since \( 64 = 4^3 \). 3. **Conclusion**: - Since \( \sqrt[3]{64} = 4 \) is a whole number, it is not a surd. ### Step 3: Analyze \( \sqrt[3]{25} \times \sqrt[3]{40} \) 1. **Combine the cube roots**: - \( \sqrt[3]{25} \times \sqrt[3]{40} = \sqrt[3]{25 \times 40} = \sqrt[3]{1000} \) 2. **Find the prime factorization of 1000**: - \( 1000 = 10^3 \) 3. **Check for perfect cubes**: - Since \( 1000 \) is a perfect cube, \( \sqrt[3]{1000} = 10 \). 4. **Conclusion**: - Since \( \sqrt[3]{1000} = 10 \) is a whole number, it is not a surd. ### Final Summary - \( \sqrt{180} \) is a surd. - \( \sqrt[3]{64} \) is not a surd. - \( \sqrt[3]{25} \times \sqrt[3]{40} \) is not a surd.
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