Home
Class 9
MATHS
The age of a man is twice the sum of the...

The age of a man is twice the sum of the age of his two children . After 20 years his age will be equal to the sum of the age of his children, at that time. Find the present age of the sum.

Text Solution

Verified by Experts

The correct Answer is:
`40`
Promotional Banner

Topper's Solved these Questions

  • SIMULTANEOUS LINEAR EQUATIONS IN TWO VARIABLES

    ICSE|Exercise Topic 2 (3 Marks questions)|12 Videos

  • SIMULTANEOUS EQUATIONS

    ICSE|Exercise EXERCISE 6 (G)|13 Videos

  • SOLIDS

    ICSE|Exercise Exercise 21(C )|10 Videos

Similar Questions

Explore conceptually related problems

The age of the father is twice the sum of the ages of his two children. After 20 yr, his age will be equal to the sum of the ages of his children. Find the age of the father.

Father’s age is three times the sum of ages of his two children. After 5 years his age will be twice the sum of ages of two children. Find the age of father.

The present age of a father is equal to the sum of the ages of his 5 children. 12 years hence, the sum of the ages of his children will be twice the ages of their father. Find the present age of the father.

The age of a father is twice the square of the age of his son. Eight years hence, the age of his father will be 4 years more than 3 times the age of the son. Find their present ages.

The sum of the ages of a man and his son is 45 years. Five years ago, the product of their ages was four times the man’s age at the time. Find their present ages.

A father is three times as old as his son. After twelve years, his age will be twice as that of his son then. Find their present ages.

A father is three times as old as his son. After twelve years, his age will be twice as that of his son then. Find their present ages.

A man is 24 years older than his son. After 2 years, the man's age will be three times that of his son. Find their present ages.

A man is 24 years older than his son. In 2 years, his age will be twice the age of his son. Find their present ages.

The present age of a man is twice that of his son. Eight years hence, their ages will be in the ratio 7:4 . Find their present ages.