Home
Class 9
MATHS
The taxi charges in a city consist of a ...

The taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For a distance of 10 km, the charge paid is `315rs` and for a journey of 15km, the charge paid is `465rs`. What are the fixed charges and the charge per kilometre ? How much does a person have to pay for travelling a distance of `32km ` ?

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of taxi charges, we will set up a system of equations based on the information provided. Let's break it down step by step. ### Step 1: Define Variables Let: - \( x \) = fixed charge (in rupees) - \( y \) = charge per kilometer (in rupees) ### Step 2: Set Up the Equations From the information given: 1. For a distance of 10 km, the total charge is 315 rupees: \[ x + 10y = 315 \quad \text{(Equation 1)} \] 2. For a distance of 15 km, the total charge is 465 rupees: \[ x + 15y = 465 \quad \text{(Equation 2)} \] ### Step 3: Solve the Equations We can solve these equations simultaneously. First, we can express \( x \) from Equation 1: \[ x = 315 - 10y \quad \text{(Substituting into Equation 2)} \] Now, substitute this expression for \( x \) into Equation 2: \[ (315 - 10y) + 15y = 465 \] ### Step 4: Simplify and Solve for \( y \) Combine like terms: \[ 315 - 10y + 15y = 465 \] \[ 315 + 5y = 465 \] Now, isolate \( y \): \[ 5y = 465 - 315 \] \[ 5y = 150 \] \[ y = \frac{150}{5} = 30 \] ### Step 5: Substitute \( y \) Back to Find \( x \) Now that we have \( y \), we can find \( x \): \[ x = 315 - 10 \cdot 30 \] \[ x = 315 - 300 = 15 \] ### Step 6: Summary of Charges - Fixed charge \( x = 15 \) rupees - Charge per kilometer \( y = 30 \) rupees ### Step 7: Calculate Charge for 32 km To find out how much a person has to pay for traveling a distance of 32 km: \[ \text{Total charge} = x + 32y \] \[ \text{Total charge} = 15 + 32 \cdot 30 \] \[ = 15 + 960 = 975 \] ### Final Answer The fixed charge is 15 rupees, the charge per kilometer is 30 rupees, and the total charge for traveling 32 km is 975 rupees. ---
Promotional Banner

Topper's Solved these Questions

  • SIMULTANEOUS LINEAR EQUATIONS IN TWO VARIABLES

    ICSE|Exercise Topic 2 (3 Marks questions)|12 Videos
  • SIMULTANEOUS EQUATIONS

    ICSE|Exercise EXERCISE 6 (G)|13 Videos
  • SOLIDS

    ICSE|Exercise Exercise 21(C )|10 Videos

Similar Questions

Explore conceptually related problems

The taxi charges in a city comprise of a fixed charge together with the charge for the distance covered. For a journey of 10 km the charge paid is Rs 75 and for a journey of 15 km the charge paid is Rs 110. What will a person have to pay for travelling a distance of 25 km?

The car hire charges in a city comprise of a fixed charges together with the charge for the distance covered. For a journey of 12 km, the charge paid is Rs 89 and for a journey of 20 km, the charge paid is Rs 145. What will a person have to pay for travelling a distance of 30 km?

The force between two charges 4C and -2C which are separated by a distance of 3km is

For 100 km, a taxi charges Rs. 1,800. How much will it charge for a journey of 120 km ?

A lending library has a fixed charge for the first three days and an additional charge for each day thereafter. Saritha paid Rs 27 for a book kept for seven days, while Susy paid Rs 21 for the book she kept for five days. Find the fixed charge and the charge for each extra day.

A point charge q is placed at the origin . How does the electric field due to the charge very with distance r from the origin ?

The force between two similar charges of magnitude 2C each separated by a distance 2km

Two fixed charges 4Q (positive) and Q (negative) are located at A and B. the distance AB being 3 m.

A particle of mass m and charge q is located midway between two fixed charged particles each having a charge q and at a distance 2L apart so that distance of this charge from each charge located at end is L. Assuming that the middle charge moves along the line joining the fixed charges. The frequency of oscillation when it is displaced slightly is

A particle of mass 100 gm and charge 2muC is released from a distance of 50 cm from a fixed charge of 5muC . Find the speed of the particle when its distance from the fixed charge becomes 3 m.