The following figure shows a solid of uniform cross-section. Find the volume of the solid.
All measurements are in centimetres. Assume that all angles in the figure are right angles.

Answer

To find the volume of the solid with a uniform cross-section, we will break it down into two cuboids and calculate their individual volumes before summing them up.

### Step-by-Step Solution:

1. **Identify the Dimensions of the First Cuboid:**
- Length (L1) = 9 cm
- Breadth (B1) = 4 cm
- Height (H1) = 3 cm

2. **Calculate the Volume of the First Cuboid:**
- The formula for the volume of a cuboid is:
\[ \text{Volume} = \text{Length} \times \text{Breadth} \times \text{Height} \]
- Substituting the dimensions:
\[ \text{Volume of First Cuboid} = L1 \times B1 \times H1 = 9 \times 4 \times 3 \]
- Calculating:
\[ 9 \times 4 = 36 \]
\[ 36 \times 3 = 108 \text{ cm}^3 \]

3. **Identify the Dimensions of the Second Cuboid:**
- Length (L2) = 4 cm
- Breadth (B2) = 6 cm
- Height (H2) = 3 cm

4. **Calculate the Volume of the Second Cuboid:**
- Using the same volume formula:
\[ \text{Volume of Second Cuboid} = L2 \times B2 \times H2 = 4 \times 6 \times 3 \]
- Calculating:
\[ 4 \times 6 = 24 \]
\[ 24 \times 3 = 72 \text{ cm}^3 \]

5. **Calculate the Total Volume of the Solid:**
- Add the volumes of both cuboids:
\[ \text{Total Volume} = \text{Volume of First Cuboid} + \text{Volume of Second Cuboid} \]
\[ \text{Total Volume} = 108 \text{ cm}^3 + 72 \text{ cm}^3 = 180 \text{ cm}^3 \]

### Final Answer:
The volume of the solid is \( \text{180 cm}^3 \).

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