For triangle ABC, show that : (i) "sin...

For triangle ABC, show that :
(i) `"sin" (A + B)/(2) = "cos" (C)/(2)`
(ii) `"tan" (B + C)/(2) = "cot" (A)/(2)`

Verified by Experts

The correct Answer is:

LHS = RHS

TRIGONOMETRY
ICSE|Exercise TOPIC -4 ( COMPLEMENTARY ANGLES ) (4 MARKS QUESTIONS )|4 Videos
TRIGONOMETRY
ICSE|Exercise TOPIC -3 ( SOLUTION OF RIGHT TRIANGLES ANGLES ) (4 MARKS QUESTIONS )|5 Videos
TRIGONOMETRICAL RATIOS OF STANDARD ANGLES
ICSE|Exercise EXERCISE 23(C)|118 Videos

Similar Questions

Explore conceptually related problems

For triangle ABC, show that "sin"(A+B)/2="cos"C/2

For triangle ABC, show that: sin((A+B)/(2))-cos(C)/(2)=0

For triangle ABC, show that "tan"(B+C)/2="cot"A/2

In any triangle ABC, show that : 2a cos (B/2) cos (C/2) = (a+b+c) sin (A/2)

In any triangle ABC, show that : 2a sin (B/2) sin (C/2)=(b+c-a) sin (A/2)

For any triangle ABC, prove that (a-b)/c=(sin((A-B)/2))/(cos(C/2))

If A + B + C = pi , then show that sin (A + B + C)/( 2) = sin(A / 2) * cos "" (B + C)/( 2) + sin "" (B + C)/( 2) * cos "" (A) / (2)

For any triangle ABC, prove that (b+c)cos((B+C)/2)=acos((B-C)/2)

In Delta ABC, "cot"(A)/(2) + "cot" (B)/(2) + "cot" (C)/(2) is equal to

In a triangle ABC, prove that (a) cos(A + B) + cos C = 0 (b) tan( (A+B)/2)= cot(C/ 2)