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If the mean of the observation a , a + 6...

If the mean of the observation a , a + 6 , a + 2 , a + 8 and a + 4 is 11 . Find .
the value of a

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To find the value of \( a \) given that the mean of the observations \( a, a + 6, a + 2, a + 8, \) and \( a + 4 \) is 11, we can follow these steps: ### Step 1: Write down the formula for the mean. The mean of a set of observations is calculated by taking the sum of all observations and dividing it by the number of observations. In this case, we have 5 observations. \[ \text{Mean} = \frac{\text{Sum of observations}}{\text{Number of observations}} \] ### Step 2: Set up the equation using the given mean. We know that the mean is 11, so we can set up the equation as follows: \[ 11 = \frac{a + (a + 6) + (a + 2) + (a + 8) + (a + 4)}{5} \] ### Step 3: Simplify the sum of the observations. Now, let's simplify the sum of the observations in the numerator: \[ a + (a + 6) + (a + 2) + (a + 8) + (a + 4) = a + a + 6 + a + 2 + a + 8 + a + 4 \] Combining like terms, we get: \[ 5a + (6 + 2 + 8 + 4) = 5a + 20 \] ### Step 4: Substitute the simplified sum back into the equation. Now, we can substitute this back into our mean equation: \[ 11 = \frac{5a + 20}{5} \] ### Step 5: Multiply both sides by 5 to eliminate the denominator. To eliminate the fraction, multiply both sides of the equation by 5: \[ 11 \times 5 = 5a + 20 \] This simplifies to: \[ 55 = 5a + 20 \] ### Step 6: Solve for \( a \). Now, we can solve for \( a \) by isolating it on one side of the equation. First, subtract 20 from both sides: \[ 55 - 20 = 5a \] This gives us: \[ 35 = 5a \] Now, divide both sides by 5: \[ a = \frac{35}{5} = 7 \] ### Final Answer: The value of \( a \) is \( 7 \). ---
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