A battery is designed by connecting four cells, each of emf 1.5 V and resistance 2.0 ohm in parallel. If this battery is now connected to an resistance of 2.5 ohm, find
the current flowing in the external circuit

A battery is designed by connecting four cells, each of emf 1.5 V and resistance 2.0 ohm in parallel. If this battery is now connected to an resistance of 2.5 ohm, find the total resistance of the circuit

A battery is designed by connecting four cells, each of emf 1.5 V and resistance 2.0 ohm in parallel. If this battery is now connected to an resistance of 2.5 ohm, find the potential drop across the terminal of the cells.

24 cells of emf 1.5 V each having internal resistance of 1 ohm are connected to an external resistance of 1.5 ohms. To get maximum current,

24 cells, each of emf 1.5V and internal resistance is 2Omega connected to 12Omega series external resistance. Then,

cells each of emf e and internal resistance r are joined in series to form a row and such rows are connected in parallel to form a battery of N = mn cells. If this battery is connected to an external resistance R . Show that current f flowing through the external resistance R is given by : I=(Ne)/(mR+nr)

A battery of emf 2V and internal resistance 0.5(Omega) is connected across a resistance 1.5(Ω). Find the current flow through battery ?

A battery has e.m.f. 4 V and internal resistance r . When this battery is connected to an external resistance of 2 ohms , a current of 1 amp . flows in the circuit. How much current will flow if the terminals of the battery are connected directly

Two cells having emf's of 10 V and 8 V, and internal resistance of 1Omega (each) are connected as shown with an external resistance of 8Omega Find the current flowing through the circuit.

A student is asked to connected four cells of e.m.f of 1 V and internal resistance 0.5 ohm in series with a external resistance of 1 ohm. But one cell is wrongly connected by him with its terminal reversed, the current in the circuit is

A coil of self inductance 2.5 H and resistance 20 Omega is connected to a battery of emf 120 V having internal resistance of 5 Omega . Find : The current in the circuit in steady state.