How much `PCI_5` must be taken in a 9.2 L vessel to get 0.5 moles of `Cl_2` at a particular temperature? The value of equilibrium constant `(K_c)` at the given temperature is 0.0414.

Given that equilibrium constant for the reaction 2SO_(2)(g) + O_(2)(g)hArr2SO_(3)(g) has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature ? SO_(3)(g)hArrSO_(2)(g) + (1)/(2)O_(2)(g)

For the reaction, A(g)+2B(g)hArr2C(g) one mole of A and 1.5 mol of B are taken in a 2.0 L vessel. At equilibrium, the concentration of C was found to be 0.35 M. The equilibrium constant (K_(c)) of the reaction would be

If degree of dissociation is 0.5 at equilibrium then the equilibrium constant K_c for the given reaction is , 2HI

2.0 mole of PCl_(5) were nttoducedd in a vessel of 5.0 L capacity of a particular temperature At equilibrium, PCl_(5) was found to be 35 % dissociated into PCl_(3)and Cl_(2) the value of K_(c) for the reaction PCl_(3)(g)+Cl_(2)(g)hArrPCl_(5)(g)

If 0.5 mole H_(2) is reacted with 0.5 mole I_(2) in a ten - litre container at 444^(@)C and at same temperature value of equilibrium constant K_(C) is 49, the ratio of [Hl] and [l_(2)] will be :

0.1 mol of PCl_(5) is vaporised in a litre vessel at 260^(@)C . Calculate the concentration of Cl_(2) at equilibrium, if the equilibrium constant for the dissociation of PCl_(5) is 0.0414 .

One mole of PCl_5 is heated in a 2L vessel. When equilibrium is attained, the vessel is found to contain 0.2 moles of PCl_5 Calculate the equilibrium constant.

2 mole of PCI_(5) were heated in a 5 litre vessel. It dissociated. 80% at equilibrium find out the value of equilibrium constatn. Report your answer as K_(C)xx50 .

A quantity of PCI _5 was heated in a 2 litre vessel at 525 K . It dissociates as PCI_5 (g) hArr PCI _3 (g) + CI_2 (g) At equilibrium 0.2 mol each of PCI_5 , PCl_3and Cl_2 is found in the reaction mixture. The equilibrium constant K_c for the reaction is -

In a vessel of 5L,26 moles of A and 4 moles of B were placed. At equilibrium 1 mole of C was present. The K_(C) for the reaction : A+2BhArrC is