How does `K_2[PtCl_4]` gets ionized when dissolved in water? Will it form precipitate when `AgNO_3` solution is added to it? Give a reason for your answer.

Explanation

`K_(2)[PtCl_(4)] to 2K^(+)+ [PtCl_(4)]^(2-)`
It will not form precipitate with `AgNO_(3)` solution because `Cl^(-)` ion is not free to form white precipitate of AgCl.