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In a first order reaction, 10% of the re...

In a first order reaction, 10% of the reactant is consumed in 25 minuts. Calculate:
The half life of the reaction.

Text Solution

Verified by Experts

t=25 minutes a `100,x=10`
`t=(2.303)/(t)"log"_(10)(a)/(a-x)`
`=(2.303)/(25)"log"_(10)(100)/(90)`
`=(2.303)/(25)log_(10)10`
`=0.0042 "min"^(-2)`
`=(0.693)/(0.0042)`
=165 min
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